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【金乡网站源码】【源码网整站源码下载】【源码酷1011源码酷】strtoint源码

时间：2024-11-19 06:20:09 来源：postern源码作者：arduino自制cnc源码

1.什么格式的源码变量可以装下50亿的阶乘?
2.Incompatible types: 'Integer' and 'String'

strtoint源码

什么格式的变量可以装下50亿的阶乘?

用数组的方法来存储。。源码

以下是源码本人对大数阶乘的研究：

一个学计算机的哥们问的问题，用数组求阶乘。源码金乡网站源码。源码。源码源码网整站源码下载即为了避免溢出、源码以及显示出阶乘的源码每一位结果。。源码

经过思考，源码我觉得用矩阵相乘的源码原理来作比较简单。。源码

下面是源码源码酷1011源码酷在 Matlab 中写的求阶乘的代码：

function JC(n)

A=1;

q=1;

for i=1:1:n

tmp=i;

p=0;

z=0;

while tmp>0

p=p+1;

B(p)=tmp-fix(tmp/)*;

tmp=fix(tmp/);

end

bb=zeros(1,p);

for ii=1:1:p

bb(p+1-ii)=B(ii);

end

for jj=1:1:p

B(jj)=bb(jj);

end

H=zeros(p,p+q-1);

for a=1:1:p

for b=1:1:q

H(a,a+b-1)=B(a).*A(b);

end

D=zeros(1,p+q-1);

for c=1:1:p+q-1

for d=1:1:p

D(c)=D(c)+H(d,c);

end

E(p+q-1)=D(p+q-1);

for w=p+q-2:-1:1

E(w)=D(w)+fix(E(w+1)/);

end

A(1)=E(1);

for x=2:1:p+q-1

A(x)=E(x)-fix(E(x)/)*;

end

r=length(A)-1;

while A(1)>0

z=z+1;

F(z)=A(1)-fix(A(1)/)*;

A(1)=fix(A(1)/);

end

G=zeros(1,z+r);

for y=z+1:1:z+r

G(y)=A(y-z+1);

end

for v=1:1:z

G(v)=F(z-v+1);

end

for s=1:1:z+r

A(s)=G(s);

end

q=z+r;

end

d=0;

for i=q:-1:1

if A(i)==0

d=d+1;

else

break;

end

最后的结果：

A：以数组的方式显示出阶乘的结果

q：阶乘结果的位数

d：阶乘结果的尾部连续出现的0的个数。

下面是源码在 delphi 中的源码：

unit Unit1;

interface

uses

Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,

Dialogs, StdCtrls, XPMan;

type

TForm1 = class(TForm)

GroupBox1: TGroupBox;

Edit1: TEdit;

Button1: TButton;

Button2: TButton;

Memo1: TMemo;

GroupBox2: TGroupBox;

GroupBox3: TGroupBox;

Edit2: TEdit;

GroupBox4: TGroupBox;

Edit3: TEdit;

XPManifest1: TXPManifest;

procedure Button1Click(Sender: TObject);

procedure Button2Click(Sender: TObject);

procedure FormActivate(Sender: TObject);

procedure Edit1KeyPress(Sender: TObject; var Key: Char);

private

{ Private declarations }

public

{ Public declarations }

end;

var

Form1: TForm1;

implementation

{ $R *.dfm}

procedure TForm1.Button1Click(Sender: TObject);

Var

A,B,bb,D,E,F,G:array of integer;

C:array of array of integer;

N,i,ii,jj,LenA,LenB,LenT,tmp,r,Ze:integer;

S:string;

begin

Memo1.Clear;

LenA:=1;

Setlength(A,LenA);

A[0]:=1;

if Edit1.Text='' then

exit

else

begin

N:=strtoint(Edit1.Text);

for i:=1 to N do

begin

tmp:=i;

LenB:=0;

LenT:=0;

while tmp>0 do

begin

LenB:=LenB+1;

Setlength(B,lenB);

B[LenB-1]:=tmp-Trunc(tmp/)*;

tmp:=Trunc(tmp/);

end;

Setlength(bb,LenB);

for ii:=1 to lenB do

bb[LenB-ii]:=B[ii-1];

for ii:=1 to LenB do

B[ii-1]:=bb[ii-1];

Setlength(C,LenB,LenB+LenA-1);

for ii:=1 to LenB do

for jj:=1 to LenA+LenB-1 do

C[ii-1,jj-1]:=0;

for ii:=1 to LenB do

for jj:=1 to LenA do

C[ii-1,ii+jj-2]:=B[ii-1]*A[jj-1];

Setlength(D,LenB+LenA-1);

for ii:=1 to LenB+LenA-1 do

D[ii-1]:=0;

for ii:=1 to LenB+LenA-1 do

for jj:=1 to LenB do

D[ii-1]:=D[ii-1]+C[jj-1,ii-1];

Setlength(E,LenB+LenA-1);

E[LenB+LenA-2]:=D[LenB+LenA-2];

for ii:=LenB+LenA-2 downto 1 do

E[ii-1]:=D[ii-1]+Trunc(E[ii]/);

Setlength(A,LenB+LenA);

A[0]:=E[0];

for ii:=2 to LenB+LenA-1 do

A[ii-1]:=E[ii-1]-Trunc(E[ii-1]/)*;

r:=LenA+LenB-2;

while A[0]>0 do

begin

LenT:=LenT+1;

Setlength(F,LenT);

F[LenT-1]:=A[0]-Trunc(A[0]/)*;

A[0]:=Trunc(A[0]/);

end;

Setlength(G,lenT+r);

for ii:=LenT+1 to LenT+r do

G[ii-1]:=A[ii-LenT];

for ii:=1 to LenT do

G[ii-1]:=F[LenT-ii];

for ii:=1 to LenT+r do

A[ii-1]:=G[ii-1];

LenA:=LenT+r;

Setlength(A,LenA);

end;

Edit2.Text:=inttostr(LenA);

Ze:=0;

for i:=LenA downto 1 do

begin

if A[i-1]=0 then

Ze:=Ze+1

else

break;

end;

Edit3.Text:=inttostr(Ze);

S:='';

for i:=1 to LenA do

S:=S+inttostr(A[i-1]);

Memo1.Lines.Add(S);

end;

procedure TForm1.Button2Click(Sender: TObject);

begin

Memo1.Clear;

Edit1.Text:='';

Edit2.Text:='';

Edit3.Text:='';

end;

procedure TForm1.FormActivate(Sender: TObject);

begin

Edit1.SetFocus;

end;

procedure TForm1.Edit1KeyPress(Sender: TObject; var Key: Char);

begin

if(key<>#8)and(key<>#)and(key<#)or(key>#)then

key:=#0;

if(key=#)then

Button1Click(sender);

end;

end.

Delphi 中用动态数组不像 Matlab那么方便。。源码但是交易所源码源码运算速度比 Matlab 快了很多，基本上是Matlab 运算速度的4倍左右，在我的机子上(Pentuim M 1.7GHz,MB内存)计算的阶乘时Dephi 用了不到秒，Matlab 用了大概2分钟。源码和复制源码区别。

在百度中搜索：质数用数组求阶乘

即可看到偶在“大富翁论坛”中发的帖子。。希望对你有帮助。。

Incompatible types: 'Integer' and 'String'

å¥½åçè¿æ¨çé®é¢ï¼å ä¸ºæ²¡æçæï¼æææ²¡æäººåçï¼ä½ çæææ¯ æ ¹æ® açå¼ï¼memo1.Text := 'æ¨çåçå¨é¨æ£ç¡®ï¼â

è¿é åºè¯¥è¿æ ·åï¼ï¼æºç ï¼ï¼

unit Unit1;

interface

uses

Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,

Dialogs, StdCtrls;

type

TForm1 = class(TForm)

Memo1: TMemo;

ListBox1: TListBox;

procedure FormCreate(Sender: TObject);

procedure ListBox1Click(Sender: TObject);

private

{ Private declarations }

public

{ Public declarations }

end;

var

Form1: TForm1;

implementation

{ $R *.dfm}

procedure TForm1.FormCreate(Sender: TObject);

begin

ListBox1.Items.Add('4');

ListBox1.Items.Add('å¯¹');

ListBox1.Items.Add('é');

ListBox1.Items.Add('å½æ°');

ListBox1.Items.Add('æ¢è¡');

ListBox1.Items.Add('ä¸æ¯');

ListBox1.Items.Add('èµ°äº');

ListBox1.Items.Add('é');

ListBox1.Items.Add('å¯¹');

ListBox1.Items.Add('delphi');

end;

procedure TForm1.ListBox1Click(Sender: TObject);

var

a:integer;

begin

a := ListBox1.ItemIndex;

case a of

0:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

1:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

2:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

3:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

4:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

5:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

6:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

7:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

8:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

9:memo1.Text := ListBox1.Items[a]+' æ¨çåçå¨é¨æ£ç¡®ï¼';

end;

end.

-------------------------------------------------

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【金乡网站源码】【源码网整站源码下载】【源码酷1011源码酷】strtoint源码

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